14+27y=20y^2

Solution for 14+27y=20y^2 equation:

14+27y=20y^2

We move all terms to the left:

14+27y-(20y^2)=0

determiningTheFunctionDomain
-20y^2+27y+14=0

a = -20; b = 27; c = +14;
Δ = b2-4ac
Δ = 272-4·(-20)·14
Δ = 1849
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1849}=43$
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(27)-43}{2*-20}=\frac{-70}{-40}
=1+3/4
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(27)+43}{2*-20}=\frac{16}{-40}
=-2/5
$